(6a-3a^2)+2a^2-3a=)

Solution for (6a-3a^2)+2a^2-3a=) equation:

(6a-3a^2)+2a^2-3a=)

We move all terms to the left:

(6a-3a^2)+2a^2-3a-())=0

We add all the numbers together, and all the variables

2a^2+(6a-3a^2)-3a=0

We get rid of parentheses

2a^2-3a^2+6a-3a=0

We add all the numbers together, and all the variables

-1a^2+3a=0

a = -1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-1)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-1}=\frac{-6}{-2}
=+3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-1}=\frac{0}{-2}
=0
$